A 12 m long bar pivoted on the right end has a 150 N upward force applied on the left end. What is the moment of force?

Study for the ABSA 4th Class Power Engineer Test. Explore questions with hints and explanations. Get ready to ace the exam!

To determine the moment of force, you can use the formula for torque, which is the product of the force applied and the distance from the pivot point to the point of application of the force. In this scenario, the force of 150 N is applied at the left end of a 12 m long bar, with the right end being the pivot point.

Since the force is applied at a distance of 12 m from the pivot, the moment (torque) can be calculated as follows:

Moment of force = Force × Distance

Moment of force = 150 N × 12 m

Calculating this gives:

Moment of force = 1800 N·m or 1.8 kNm.

This means that the moment of force exerted by the 150 N upward force applied at the left end of the bar, in relation to the pivot point on the right end, is indeed 1.8 kNm.

The correct answer is reflective of both the magnitude and direction of the forces involved, which follow the principles of static equilibrium and rotational dynamics. Understanding this relationship is crucial for power engineers, as it applies directly to torque calculations in various engineering applications.

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