A 15 m long bar is pivoted on the right end with a downward force of 5 N on the left end. The moment of force is?

The moment of force, also known as torque, is calculated by multiplying the force applied by the distance from the pivot point to the point where the force is applied. In this scenario, a downward force of 5 N is applied at the left end of a 15 m long bar, while the pivot is located at the right end.

To calculate the moment of force, use the formula:

[ \text{Moment} = \text{Force} \times \text{Distance} ]

Here, the distance from the left end (where the force is applied) to the pivot point (at the right end) is 15 m. Thus, you can calculate the moment as follows:

[ \text{Moment} = 5 , \text{N} \times 15 , \text{m} = 75 , \text{Nm} ]

Since the force is acting downward on the left end of the bar and the pivot is on the right end, this force creates a counter-clockwise moment about the pivot. Therefore, the direction of the torque is counter-clockwise, reinforcing that the effective moment of force is 75 Nm counter-clockwise.

This result aligns with the correct answer, where the