A car has an initial speed of 35 km/h and in 75 seconds it accelerates to 120 km/h. What is the distance travelled during the acceleration period?

Study for the ABSA 4th Class Power Engineer Test. Explore questions with hints and explanations. Get ready to ace the exam!

To find the distance traveled during the acceleration period, we first need to calculate the acceleration and then use that to determine the distance.

  1. Calculate acceleration: The car's initial speed is 35 km/h, which needs to be converted to meters per second for consistency in units. There are 1000 meters in a kilometer and 3600 seconds in an hour, so:

[

\text{Initial speed} = 35 , \text{km/h} = \frac{35 \times 1000}{3600} \approx 9.72 , \text{m/s}

]

The final speed is 120 km/h, converted similarly:

[

\text{Final speed} = 120 , \text{km/h} = \frac{120 \times 1000}{3600} \approx 33.33 , \text{m/s}

]

The change in speed (Δv) is:

[

\Delta v = \text{Final speed} - \text{Initial speed} = 33.33 , \text{m/s} - 9.72 , \text{

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