A car has an initial speed of 25 km/h and in 84 seconds it accelerates to 110 km/h. What is the distance travelled during the acceleration period?

Study for the ABSA 4th Class Power Engineer Test. Explore questions with hints and explanations. Get ready to ace the exam!

To find the distance traveled during the acceleration period, we first need to calculate the acceleration and then apply the formula for distance under uniform acceleration.

The initial speed of the car is 25 km/h, which needs to be converted into meters per second for consistency in calculations. We convert it by using the conversion factor (1 km/h = 1/3.6 m/s):

  • Initial speed = 25 km/h * (1000 m / 1 km) / (3600 s / 1 h) = approximately 6.94 m/s

The final speed after acceleration is 110 km/h:

  • Final speed = 110 km/h * (1000 m / 1 km) / (3600 s / 1 h) = approximately 30.56 m/s

Next, we can calculate the acceleration using the formula:

  • Acceleration (a) = (Final speed - Initial speed) / Time = (30.56 m/s - 6.94 m/s) / 84 s = approximately 0.2807 m/s²

Now, we use the formula for distance traveled (d) during acceleration, which is given by:

  • d = Initial speed * Time + 0.
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