A simple machine must raise 1 tonne of stone a vertical distance of 30 m. What is the work done if the efficiency is 100%?

To determine the work done in raising a one-tonne stone a vertical distance of 30 meters with 100% efficiency, we employ the basic formula for work done, which is:

[ \text{Work} = \text{Force} \times \text{Distance} ]

In this scenario, the force involved in lifting the stone is equal to its weight. The weight can be calculated using the formula:

[ \text{Weight} = \text{mass} \times \text{gravitational acceleration} ]

Given that the mass of the stone is 1 tonne, we convert that into kilograms:

1 tonne = 1000 kg

The standard gravitational acceleration is approximately ( 9.81 , \text{m/s}^2 ). Therefore, the force exerted to raise the stone is:

[ \text{Weight} = 1000 , \text{kg} \times 9.81 , \text{m/s}^2 = 9810 , \text{N} ]

Now, we can calculate the work done in lifting the stone the vertical distance of 30 m:

[ \text{Work} = 9810 , \text{