A vehicle starts from rest and reaches 80 km/h in 12 seconds. How far does it travel in the first 12 seconds?

Study for the ABSA 4th Class Power Engineer Test. Explore questions with hints and explanations. Get ready to ace the exam!

To determine the distance traveled by a vehicle that starts from rest and accelerates to a certain speed over a specific time, we can use the formula for distance in uniformly accelerated motion. Since the vehicle starts from rest (initial velocity, u = 0), we can use the equation:

Distance (s) = u * t + (1/2) * a * t².

First, we need to calculate the acceleration (a) of the vehicle. The final velocity (v) is given as 80 km/h. To work with standard units, we convert this speed to meters per second:

80 km/h = (80 * 1000 m) / (3600 s) = 22.22 m/s.

Now, we can use the formula for acceleration, which is:

a = (v - u) / t

= (22.22 m/s - 0) / 12 s

= 22.22 m/s / 12 s

= 1.85 m/s².

Having calculated the acceleration, we can now find the distance traveled during the 12 seconds using the distance formula. Plugging in the values:

s = 0 * 12 + (1/2

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