An object is dropped from a height of 45 m. What will its velocity be on impact?

To determine the velocity of an object just before impact when it is dropped from a height of 45 meters, we can use the principles of physics pertaining to free fall. When an object is dropped from a height, it accelerates towards the ground due to gravity, which is approximately 9.81 m/s² on Earth.

The formula to calculate the final velocity (v) of an object falling from a certain height (h) is derived from the kinematic equation:

v = √(2gh)

Where:

• g = acceleration due to gravity (approximately 9.81 m/s²)

• h = height from which the object is dropped (in this case, 45 m)

Plugging in the values:

v = √(2 * 9.81 m/s² * 45 m)

v = √(882.9 m²/s²)

v ≈ 29.71 m/s

Thus, the velocity of the object when it impacts the ground would be approximately 29.71 m/s. This aligns with the fundamental principles of caused motion, establishing a clear understanding of how objects accelerate under gravity, leading to the conclusion that the correct answer is based on standard gravitational effects on falling bodies.