An object is thrown directly downwards from a height of 60 m with an initial velocity of 11 m/s. What will be its velocity on impact?

To determine the object's velocity upon impact when thrown directly downwards from a height of 60 m with an initial velocity of 11 m/s, we can employ the kinematic equations of motion. The equation most relevant in this case is:

[ v^2 = u^2 + 2gh ]

Where:

• ( v ) is the final velocity upon impact.

• ( u ) is the initial velocity (11 m/s).

• ( g ) is the acceleration due to gravity (approximately 9.81 m/s²).

• ( h ) is the height from which the object is thrown (60 m).

First, we convert the height into the equation with gravity acting downwards (positive), leading to:

[ v^2 = (11 , \text{m/s})^2 + 2 \cdot 9.81 , \text{m/s}^2 \cdot 60 , \text{m} ]

Calculating the initial velocity term:

[ (11 , \text{m/s})^2 = 121 , \text{m}^2/\text{s}^2 ]

Calculating the gravitational term:

[ 2 \