How much load can be balanced by a 100 kg mass attached to the wheel in a simple wheel and axle system with a diameter of 2 m and an axle diameter of 8 cm?

Study for the ABSA 4th Class Power Engineer Test. Explore questions with hints and explanations. Get ready to ace the exam!

To determine how much load can be balanced by a 100 kg mass in a simple wheel and axle system, we first need to understand the mechanics involved in how the system operates.

In this case, the wheel and axle system consists of a wheel with a diameter of 2 meters and a smaller axle with a diameter of 8 cm. The radius of the wheel is 1 meter (which is half of the diameter), and the radius of the axle is 0.04 meters (which is half of 8 cm).

The mechanical advantage (MA) of a wheel and axle system can be calculated using the following formula:

[ \text{Mechanical Advantage (MA)} = \frac{\text{Radius of the Wheel}}{\text{Radius of the Axle}} ]

Substituting the values:

[ MA = \frac{1 , \text{m}}{0.04 , \text{m}} = 25 ]

This implies that the force exerted at the axle can be amplified by a factor of 25 compared to the force applied at the radius of the wheel.

Next, we must calculate the weight of the 100 kg mass, which is the force exerted downward due to gravity

Subscribe

Get the latest from Examzify

You can unsubscribe at any time. Read our privacy policy