How much of B is required in a 15 kg batch mixed in a 4:6:2 ratio of A, B, and C?

Study for the ABSA 4th Class Power Engineer Test. Explore questions with hints and explanations. Get ready to ace the exam!

To determine the amount of component B required in a 15 kg batch mixed in a 4:6:2 ratio of A, B, and C, we first need to understand how the mixture ratio translates into parts. The given ratio of A, B, and C can be summarized as:

  • A = 4 parts
  • B = 6 parts

  • C = 2 parts

Adding these parts together gives a total of 4 + 6 + 2 = 12 parts.

Next, we can establish how much each part weighs in the total batch. Since the total weight of the batch is 15 kg, we can calculate the weight of one part by dividing the total weight by the total number of parts:

Weight of one part = 15 kg / 12 parts = 1.25 kg per part.

Now, to find the weight of component B, we multiply the number of parts of B by the weight of one part:

Weight of B = 6 parts × 1.25 kg/part = 7.5 kg.

This confirms that the correct amount of B required in the 15 kg mixture is indeed 7.5 kg. Understanding these calculations is crucial for applications in power engineering

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