If a body moves from Point A to Point B in a semicircular path with a diameter of 2 m, what is the distance between Point A and Point B?

Study for the ABSA 4th Class Power Engineer Test. Explore questions with hints and explanations. Get ready to ace the exam!

The distance between Point A and Point B in this scenario is determined by the fact that they are located on opposite ends of a semicircular path. Given that the diameter of the semicircle is 2 meters, we can find the distance between the two points using the diameter itself. In a semicircle, the two ends (Point A and Point B) are directly across from one another, making the distance equal to the length of the diameter.

Since the diameter of the semicircle is provided as 2 meters, the direct distance from Point A to Point B is 2 meters. However, this question might seem tricky if we are considering the length of the path traveled, which is actually the semicircular arc. The semicircular arc would be half the circumference of a full circle with that diameter. The full circumference of a circle is calculated as π multiplied by the diameter. For a circle with a diameter of 2 m, the full circumference is 2π (which is about 6.28 m). Half of this, representing the distance along the path from A to B, would be π, which is approximately 3.14 m.

Thus, the distance along the semicircular path from Point A to Point B is indeed 3

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