If a chemical mixture requires a ratio of 4 parts A, 6 parts B, and 2 parts C for a 15 kg batch, what is the quantity of A needed?

Study for the ABSA 4th Class Power Engineer Test. Explore questions with hints and explanations. Get ready to ace the exam!

To determine the quantity of each component (A, B, and C) needed in a 15 kg batch based on the ratio provided, we first need to understand the total parts in the ratio. The ratio of 4 parts A, 6 parts B, and 2 parts C sums up to a total of 12 parts (4 + 6 + 2 = 12).

Next, to find out how much each part represents in the total weight of 15 kg, we divide the total weight by the total number of parts:

15 kg / 12 parts = 1.25 kg per part.

Now, we can multiply the number of parts for each component by the weight per part:

  • For A: 4 parts * 1.25 kg/part = 5 kg

  • For B: 6 parts * 1.25 kg/part = 7.5 kg

  • For C: 2 parts * 1.25 kg/part = 2.5 kg

This calculation confirms that the quantity of A needed is indeed 5 kg, with corresponding quantities for B and C as 7.5 kg and 2.5 kg respectively.

Thus, the option that

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