If a pressure of 1,100 kPa acts on a circular wall with a diameter of 3 m, what force is produced?

If a pressure of 1,100 kPa acts on a circular wall with a diameter of 3 m, what force is produced?

• A. 7,775.44 kN
• B. 155 kN
• C. 31,101 kN
• D. 10,367.26 kN

Answer: (A)

To calculate the force produced by a pressure acting on a circular wall, the relationship between pressure, area, and force is used. The force can be calculated with the formula: \[ \text{Force} = \text{Pressure} \times \text{Area} \] First, we need to find the area of the circular wall. The area \( A \) of a circle is given by the formula: \[ A = \pi \left( \frac{d}{2} \right)^2 \] where \( d \) is the diameter of the circle. Given that the diameter is 3 m, the radius \( r \) would be: \[ r = \frac{3 \, \text{m}}{2} = 1.5 \, \text{m} \] Now, we can calculate the area: \[ A = \pi (1.5 \, \text{m})^2 \approx 3.14 \times 2.25 \approx 7.06858 \, \text{m}^2 \] With the pressure given as 1,100 kPa (which is equivalent to 1,100,000 Pa since 1 kPa

To calculate the force produced by a pressure acting on a circular wall, the relationship between pressure, area, and force is used. The force can be calculated with the formula:

[ \text{Force} = \text{Pressure} \times \text{Area} ]

First, we need to find the area of the circular wall. The area ( A ) of a circle is given by the formula:

[ A = \pi \left( \frac{d}{2} \right)^2 ]

where ( d ) is the diameter of the circle. Given that the diameter is 3 m, the radius ( r ) would be:

[ r = \frac{3 , \text{m}}{2} = 1.5 , \text{m} ]

Now, we can calculate the area:

[ A = \pi (1.5 , \text{m})^2 \approx 3.14 \times 2.25 \approx 7.06858 , \text{m}^2 ]

With the pressure given as 1,100 kPa (which is equivalent to 1,100,000 Pa since 1 kPa