If the effort to lift a 150 kg load is decreased to 150 N while using a pulley system, what will the maximum load capacity be if the mechanical advantage is 10?

Study for the ABSA 4th Class Power Engineer Test. Explore questions with hints and explanations. Get ready to ace the exam!

In a pulley system, the mechanical advantage (MA) allows you to lift a load more easily by applying a smaller effort than the actual weight of the load. The mechanical advantage is defined as the ratio of the load force to the effort force.

In this scenario, the load is 150 kg, which weighs approximately 1,470 N (calculated as mass multiplied by the acceleration due to gravity, where gravity is roughly 9.81 m/s²). However, the problem states that the effort needed to lift this load is decreased to 150 N while using a pulley system that has a mechanical advantage of 10.

To find the maximum load capacity, you multiply the effort force by the mechanical advantage. With an effort of 150 N and an MA of 10, the calculation is as follows:

Maximum load capacity = Effort force × Mechanical advantage = 150 N × 10 = 1,500 N.

Therefore, based on this calculation, the correct answer indicating the maximum load capacity that can be lifted with this configuration is indeed 1,500 N.

It's important to note that despite the incorrect answer being identified as 1,000 N, the mechanics involved clearly justify 1,500 N based on the established

Subscribe

Get the latest from Examzify

You can unsubscribe at any time. Read our privacy policy