In a 4,000 L swimming pool that requires 3 parts chlorine liquid for every 100 parts water, how much chlorine liquid is needed?

Study for the ABSA 4th Class Power Engineer Test. Explore questions with hints and explanations. Get ready to ace the exam!

To determine the amount of chlorine liquid needed for a 4,000 L swimming pool that requires a concentration of 3 parts chlorine liquid for every 100 parts water, we start by calculating the total number of parts represented by the water and chlorine combined.

Since you have 100 parts water and 3 parts chlorine, this gives a total of 103 parts (100 parts of water + 3 parts of chlorine). The ratio of chlorine to the total solution is therefore ( \frac{3}{103} ).

Next, we need to find out how many liters of chlorine correspond to the 4,000 L of the swimming pool water. The formula to calculate this is:

[

\text{Chlorine Volume} = \text{Total Volume} \times \frac{\text{Chlorine Parts}}{\text{Total Parts}}

]

Substituting in the numbers gives us:

[

\text{Chlorine Volume} = 4000 , \text{L} \times \frac{3}{103} \approx 116.50 , \text{L}

]

This calculation indicates that there might be a need to refine the answer slightly; however, when rounding to the nearest

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