In a drive belt system with an input of 265 kW and an output of 211 kW, what is the efficiency?

Study for the ABSA 4th Class Power Engineer Test. Explore questions with hints and explanations. Get ready to ace the exam!

To determine the efficiency of the drive belt system, you can use the formula for efficiency, which is defined as the ratio of output power to input power, expressed as a percentage. The formula is:

Efficiency (%) = (Output Power / Input Power) × 100

Given the input power of 265 kW and output power of 211 kW, you would substitute these values into the formula:

Efficiency = (211 kW / 265 kW) × 100

Calculating this gives:

Efficiency = (0.796226415) × 100 ≈ 79.6%

This result indicates that approximately 79.6% of the input power is converted into useful output power, while the remainder is lost, likely due to factors such as friction, slippage, or inefficiencies in the system.

This percentage effectively reflects the performance of the drive belt system, aligning with the characteristics typically observed in mechanical systems. Therefore, the calculated efficiency confirms the choice of 79.6% as the correct answer.

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