In a mixture where the ratio is 9:2:5 for A, B, and C respectively, how many kg of C are in a total batch of 64 kg?

To determine how many kilograms of C are in a mixture where the components A, B, and C are in a ratio of 9:2:5, you first need to calculate the total ratio parts. In this case, you add the parts together: 9 + 2 + 5, which equals 16 parts.

Next, to find out how much each part represents in terms of mass, you divide the total mass of the mixture (64 kg) by the total number of parts (16). This gives you the mass of one part:

64 kg ÷ 16 parts = 4 kg per part.

Now you can calculate the mass of C, which is represented by 5 parts. You multiply the mass of one part by the number of parts for C:

5 parts × 4 kg/part = 20 kg.

This indicates that the total kg corresponding to C would be 20 kg, which reveals that the answer stated may not reflect the appropriate calculations.

Given this breakdown, to arrive at the option selected as D, there likely was an error in assumption about the parts or the total kg involved. Hence, verifying the arithmetic and ensuring clarity in understanding the ratio relationship is crucial for the correct answer.