What distance will an effort of 400 N move if it lifts a load of 2 kN a distance of 3 m with an efficiency of 80%?

To determine the distance that an effort of 400 N will move when lifting a load of 2 kN a distance of 3 m, given an efficiency of 80%, we can start by applying the principle of mechanical advantage (MA) and efficiency.

First, we know the formula for efficiency:

Efficiency = (Mechanical Advantage / Velocity Ratio) x 100%.

Rearranging this gives us:

Mechanical Advantage = Efficiency x Velocity Ratio.

Mechanical Advantage can be calculated as the ratio of load to effort:

MA = Load / Effort = 2000 N / 400 N = 5.

Next, if we rearrange the velocity ratio (VR) in terms of MA and efficiency, we have:

VR = MA / (Efficiency / 100) = MA / 0.80 = 5 / 0.80 = 6.25.

Now, in mechanical systems, the velocity ratio (VR) is also the ratio of the distance moved by effort to the distance moved by load:

VR = Distance moved by effort / Distance moved by load.

We know the distance moved by the load is 3 m:

6.25 = Distance moved by effort / 3 m.

To find the distance moved by the