What effort is required to raise an 850 kg load with a simple wheel and axle having a wheel diameter of 3 m and an efficiency of 87%?

Study for the ABSA 4th Class Power Engineer Test. Explore questions with hints and explanations. Get ready to ace the exam!

To determine the effort required to raise an 850 kg load using a simple wheel and axle, we must first calculate the weight of the load being lifted. The weight (force due to gravity) can be found using the formula:

Weight = mass × gravity

Weight = 850 kg × 9.81 m/s² ≈ 8,338.5 N

Next, we need to consider the efficiency of the wheel and axle system. The efficiency is given as 87%, which means that only 87% of the input work is converted to useful work for lifting the load.

To find the effort required, we can use the formula for a machine's efficiency:

Efficiency = (Output Force / Input Force) × 100%

Rearranging this gives:

Input Force = Output Force / (Efficiency / 100%)

In this scenario, the output force is the weight of the load (8,338.5 N), and the efficiency needs to be expressed as a decimal (0.87):

Input Force = 8,338.5 N / 0.87 ≈ 9,573.56 N

However, this value represents the total input force needed, and not the effective effort we must apply through the

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