What is the displacement between Point A and Point B if a body moves along a semicircular path with a radius of 2 m?

Study for the ABSA 4th Class Power Engineer Test. Explore questions with hints and explanations. Get ready to ace the exam!

The correct answer is based on the concept of displacement, which refers to the shortest straight-line distance from the initial position to the final position of an object, regardless of the path taken. In this scenario, a body moves along a semicircular path with a radius of 2 meters.

To determine the displacement between Point A and Point B, we can visualize that Point A is at one end of the semicircle and Point B is directly opposite at the other end. The radius of the semicircle is 2 meters, meaning that both points lie on the ends of a diameter of the semicircle.

The length of the diameter can be calculated using the formula for the diameter (D) in relation to the radius (r):

D = 2 * r

In this case, the diameter would be:

D = 2 * 2 m = 4 m

Therefore, the straight-line distance—essentially the displacement—from Point A to Point B, which are on the ends of the diameter, is 4 meters. This explains why the correct answer reflects the displacement in a scenario involving a semicircular motion, focusing on the shortest path between the two points.

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