What is the effort required to maintain equilibrium in the system where the axle diameter is 25 cm and the load is 2 tonnes with a mechanical advantage of 30?

To determine the effort required to maintain equilibrium in a system with a given load and mechanical advantage, you can use the formula associated with mechanical advantage:

Mechanical Advantage (MA) = Load / Effort

In this case, the load is 2 tonnes, which can be converted to Newtons (N) since 1 tonne equals 1,000 kg and the acceleration due to gravity is approximately 9.81 m/s². Thus, the load in Newtons is:

Load = 2 tonnes × 1,000 kg/tonne × 9.81 m/s² = 19,620 N

Knowing the mechanical advantage is 30, we can rearrange the formula to find the effort:

Effort = Load / MA

Substituting the values we have:

Effort = 19,620 N / 30 = 654 N

Therefore, the effort required to maintain equilibrium in this system is 654 N, making this the correct answer. Understanding how mechanical advantage translates the load to effort highlights how machines can reduce the amount of input force necessary to lift or move heavy objects.