What is the kinetic energy of a car with a mass of 1500 kg traveling at a speed of 50 km/h?

What is the kinetic energy of a car with a mass of 1500 kg traveling at a speed of 50 km/h?

• A. 30 kJ
• B. 25 kJ
• C. 144.7 kJ
• D. 289.4 kJ

Answer: (C)

To find the kinetic energy of the car, we use the formula for kinetic energy, which is given by: \[ KE = \frac{1}{2} m v^2 \] where: - \( KE \) is the kinetic energy, - \( m \) is the mass of the object (in kilograms), - \( v \) is the velocity of the object (in meters per second). First, we need to convert the speed from kilometers per hour (km/h) to meters per second (m/s). The conversion is done using the factor \( \frac{1000 \text{ m}}{1 \text{ km}} \) and \( \frac{1 \text{ h}}{3600 \text{ s}} \): \[ 50 \text{ km/h} = 50 \times \frac{1000}{3600} = \frac{50000}{3600} \approx 13.89 \text{ m/s} \] Next, we can plug the values into the kinetic energy formula: 1. Substitute \( m = 1500 \, \text{kg} \) and \( v \approx 13.89 \, \text{m/s}

To find the kinetic energy of the car, we use the formula for kinetic energy, which is given by:

[ KE = \frac{1}{2} m v^2 ]

where:

• ( KE ) is the kinetic energy,

• ( m ) is the mass of the object (in kilograms),

• ( v ) is the velocity of the object (in meters per second).

First, we need to convert the speed from kilometers per hour (km/h) to meters per second (m/s).

The conversion is done using the factor ( \frac{1000 \text{ m}}{1 \text{ km}} ) and ( \frac{1 \text{ h}}{3600 \text{ s}} ):

[ 50 \text{ km/h} = 50 \times \frac{1000}{3600} = \frac{50000}{3600} \approx 13.89 \text{ m/s} ]

Next, we can plug the values into the kinetic energy formula:

1. Substitute ( m = 1500 , \text{kg} ) and ( v \approx 13.89 , \text{m/s}