What is the speed of the belt if the tensions in the tight and slack sides of a belt are 14,000 N and 900 N, with a power transmission of 655 kW?

Study for the ABSA 4th Class Power Engineer Test. Explore questions with hints and explanations. Get ready to ace the exam!

To determine the speed of the belt in a belt drive system, you can use the formula for power transmission, which is given by:

[ P = (T_{tight} - T_{slack}) \times v ]

Where:

  • ( P ) is the power transmitted (in watts),

  • ( T_{tight} ) is the tension in the tight side of the belt (in newtons),

  • ( T_{slack} ) is the tension in the slack side of the belt (in newtons),

  • ( v ) is the speed of the belt (in meters per second).

First, we need to convert the power from kilowatts to watts:

[ 655 , kW = 655,000 , W ]

Next, calculate the difference in tension:

[ T_{tight} - T_{slack} = 14,000 , N - 900 , N = 13,100 , N ]

Now, substitute the values into the power equation:

[ 655,000 , W = 13,100 , N \times v ]

To find ( v ), rearrange the equation:

[ v = \frac{655,

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