What is the total amount of mixture if the parts of A, B, and C are 4, 6, and 2 respectively, in a total 15 kg batch?

Study for the ABSA 4th Class Power Engineer Test. Explore questions with hints and explanations. Get ready to ace the exam!

In this scenario, the amounts of substances A, B, and C are represented in a ratio of 4:6:2. To determine the total amount of the mixture, you first need to add together the parts of A, B, and C.

Adding these parts gives you:

4 (parts of A) + 6 (parts of B) + 2 (parts of C) = 12 parts total.

Next, we know that this total of 12 parts corresponds to the total weight of the mixture, which is specified as a 15 kg batch. To find out how much each part weighs, divide the total weight by the total parts:

15 kg ÷ 12 parts = 1.25 kg per part.

Then, you can check the actual weights of A, B, and C to ensure they sum up to 15 kg:

  • Weight of A = 4 parts × 1.25 kg/part = 5 kg

  • Weight of B = 6 parts × 1.25 kg/part = 7.5 kg

  • Weight of C = 2 parts × 1.25 kg/part = 2.5 kg

Adding these weights together gives you:

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