What is the volume of a cylinder with a diameter of 9 m and a height of 15 m?

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Multiple Choice

What is the volume of a cylinder with a diameter of 9 m and a height of 15 m?

Explanation:
To determine the volume of a cylinder, the formula used is: \[ V = \pi r^2 h \] where \( V \) is the volume, \( r \) is the radius, and \( h \) is the height of the cylinder. First, we need to find the radius of the cylinder. Given that the diameter is 9 m, the radius \( r \) would be half of that: \[ r = \frac{9 m}{2} = 4.5 m \] Next, the height \( h \) of the cylinder is provided as 15 m. Now, substituting the values into the volume formula: \[ V = \pi (4.5 m)^2 (15 m) \] \[ V = \pi (20.25 m^2) (15 m) \] \[ V = \pi (303.75 m^3) \] Using an approximation for \( \pi \) (approximately 3.1416): \[ V \approx 3.1416 \times 303.75 \] \[ V \approx 954.3 m^3 \] Thus, the volume of the cylinder is approximately 954.3 cubic meters.

To determine the volume of a cylinder, the formula used is:

[ V = \pi r^2 h ]

where ( V ) is the volume, ( r ) is the radius, and ( h ) is the height of the cylinder.

First, we need to find the radius of the cylinder. Given that the diameter is 9 m, the radius ( r ) would be half of that:

[ r = \frac{9 m}{2} = 4.5 m ]

Next, the height ( h ) of the cylinder is provided as 15 m.

Now, substituting the values into the volume formula:

[ V = \pi (4.5 m)^2 (15 m) ]

[ V = \pi (20.25 m^2) (15 m) ]

[ V = \pi (303.75 m^3) ]

Using an approximation for ( \pi ) (approximately 3.1416):

[ V \approx 3.1416 \times 303.75 ]

[ V \approx 954.3 m^3 ]

Thus, the volume of the cylinder is approximately 954.3 cubic meters.

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